Then use it in whatever part of your query that makes sense. ![]() This will output: REGEXP_REPLACE(REGEXP_REPLACE('input test string, 'test', '', 'gi'), 'foo', '', 'gi') So that finally, when no more substrings are in the list to remove, the final aggregated query is returned. Example: PostgreSQL ARRAYREPLACE() function. Syntax: arrayreplace(anyarray, anyelement, anyelement) Return Type: anyarray. Then, recursively calls the function again with elements and append each REGEXP query to the passed parameter. This function is used to replace each array element equal to the given value with a new value. The code splits the comma separated string to a list of substrings to remove, Creates a REGEXP_REPLACE function in sql with the first substring. I want to replace them on a condition that if. There are some array elements which are greater than 360. Replace_psql_string("test,foo", "input test string") PostgreSQL: Replace values greater than a certain limit in array elements. ![]() Return self.replace_psql_string(','.join(ss), query) I have 2 text columns where I need to replace (on update) chars from array 1 ('q','x','y','z') to their index-equivalent value in array 2 ('a','b','c','d'). This is a generic recursive function written in python (but can easily be replicated in whatever language you prefer) That takes in the original string and a list of substrings to be removed: def replace_psql_string(str_to_remove, query): Replace characters with multi-character strings The result of the update is following: Juhanao Updates table so all predefined letters are translated and the change is saved to the database. Note: There are two differences in the behavior of stringtoarray from pre-9.1 versions of PostgreSQL. update xyz set name = translate(name, 'ä,ü,Ü', 'a,u,U') In arraytostring, if the null-string parameter is omitted or NULL, any null elements in the array are simply skipped and not represented in the output string. Translates all letters ä to a, ü to u and Ü to U. The result of the update is following: JuhaenaeoĮxample of translate function: select translate(name, 'ä,ü,Ü', 'a,u,U') from xyz update xyz set name = replace(replace(replace(name, 'ä', 'ae'), 'ü', 'ue'), 'Ü', 'Ue') Ĭhanges letters and updates rows. ![]() Not very nice, but in the example all ä become ae, ü become ue, and Ü become 'Ue'. select replace(name, 'ä', 'ae') from xyz This function replaces letter ä in the name column with letter a. Some data to play with: drop table if exists xyz Įxample of replace function: select replace(name, 'ä', 'a') from xyz If you want to translate some letters to other letters you can user function translate(string text, from text, to text) that replaces any character in a string that matches a character in the from by the corresponding character in the to set. The replace function can be used to replace one character to several characters. ord, replace(string, i.oldstr, i.newstr) from recursivereplace r join inputrows i on i.ord r.ord+ 1 ) select string from recursivereplace order by ord. I have not tried that, I would rather upgrade to the current version.If you want just to replace one or few characters you can use function replace(string text, from text, to text) that replaces all occurrences in string substring. The older your version the worse are your chances. ![]() Get the patch "Add array_remove() and array_replace() functions" from the git repo, apply it to the source of your version and recompile.
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